b^2=476

Solution for b^2=476 equation:

b^2=476

We move all terms to the left:

b^2-(476)=0

a = 1; b = 0; c = -476;
Δ = b2-4ac
Δ = 02-4·1·(-476)
Δ = 1904
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1904}=\sqrt{16*119}=\sqrt{16}*\sqrt{119}=4\sqrt{119}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{119}}{2*1}=\frac{0-4\sqrt{119}}{2}
=-\frac{4\sqrt{119}}{2}
=-2\sqrt{119}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{119}}{2*1}=\frac{0+4\sqrt{119}}{2}
=\frac{4\sqrt{119}}{2}
=2\sqrt{119}
$